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| Forum topic by Built2Last | posted 556 days ago | 970 views | 0 times favorited | 8 replies | ![]() |
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556 days ago |
Ok, here’s the thing I need some smart person to help me with. I’m changing the motor on the sawmill I built a while back from a gas powered to electric. Really I have already changed it and now I am changing the electric motor. The electic motor I have on it now is a 7.5 hp that turns 3600 rpm’s. With this motor I’m running a 4 inch pulley on the motor (drive pulley) and a 14 inch on the driveshaft (driven pulley). This gives me the blade speed I need. The motor I’m changing to is a 7.5 hp also but it turns 1750 rpms. Now I know that I can run say a 3.25 inch diameter drive pulley and a 4.87 inch driven pulley to get the right blade speed. My question< is the horsepower transfered by the belts affected by the size of the pulley’s. What I mean is, if I run say a 6 inch drive and a 9 inch driven will it transfer more horsepower or will the smaller pulleys on the drive and driven shaft transfer more. If so, how much differance is there. Since the cost of pulleys can be outrageous, smaller would be better for me. I know smaller pulleys will wear out a belt faster but it also puts less strain or load on the motor bearings and belts would be cheaper to replace than bearings plus the savings using smaller pulleys is substantial. My idea now is to go with a 2 groove 3.25 on the drive pulley and a 4.9 or so 2 groove driven pulley. My center distance between pulleys will be somewhere around 18 inches or so. I think I can space then so that I can use BX56 belts since I already use then in another application and keep then on hand. If anyone knows for sure about this or just has a common sense idea about this, I would apprecaite your input. |





















