Quick question about angles for an equilateral triangle raised garden bed

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Forum topic by hypnos posted 04-11-2010 12:39 AM 9427 views 0 times favorited 4 replies Add to Favorites Watch
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28 posts in 3409 days

04-11-2010 12:39 AM

I should have paid more attention in geometry class. I have three 2×10 10’ boards, what angle should I cut on one end of each board with my circular saw to make an equilateral triangle?


-- David P., Kansas City

4 replies so far

View Les Casteel's profile

Les Casteel

160 posts in 3029 days

#1 posted 04-11-2010 01:09 AM

any triangle contains 180 degrees total. so 180/3 = 60 for each intersection. Then 60/2 =30 so you cut each board on the ends at 30 degrees.

Good Luck!

-- Les, Missouri,

View Wood_smith's profile


260 posts in 2995 days

#2 posted 04-11-2010 01:09 AM

but wouldn’t you cut both ends of each board?

-- Lloyd Kerry; creator of the Kerry-All Pouch,

View patron's profile


13600 posts in 3311 days

#3 posted 04-11-2010 01:11 AM

if you want to overlap them , 30 deg all ends ,

shopgirl is right , 60 deg is right for a miter .

all triangles equal 180 deg inside .

your picture didn’t show for a while shopgyrl ,
so i edited mine .

-- david - only thru kindness can this world be whole . If we don't succeed we run the risk of failure. Dan Quayle

View hypnos's profile


28 posts in 3409 days

#4 posted 04-11-2010 01:25 AM

Yeah, I figured out 30 degrees on the saw would do it if I cut each of the ends, I was envisioning somehow being able to just cut one end on each board so I’d be able to drive screws through a face into end grain, being able to drive as long of screws as I want – just cutting one end of each end. That’s what had me a little stumped seeing the angles. I may just have to cut each end and rely on a triangular post between each point to drive the nails in…

-Edit I just refreshed and saw the first triangle you posted shopguryl – that’s what I was thinking, except I thought I could somehow leave one end uncut, I see that would blunt the points of the triangle.

-- David P., Kansas City

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