# Help with Hexagons 2 short sides 4 long angles all 120

 Forum topic by Hoowaa posted 04-10-2016 03:56 AM 846 views 0 times favorited 20 replies
 Hoowaa14 posts in 333 days 04-10-2016 03:56 AM Topic tags/keywords: hexagon geometry catan Does anyone know where I can find a hexagon scale calculator? I am building a hexagon frame with 2 short sides and 4 long sides. All angles are 120.

## 20 replies so far

 waho6o97115 posts in 1995 days #1 posted 04-10-2016 03:59 AM Hoowaa14 posts in 333 days #2 posted 04-10-2016 04:06 AM None of them let you work with a hexagon with different side lengths. jbay699 posts in 318 days #3 posted 04-10-2016 04:07 AM give me the perimeters and I will draw it in sketch up real quik -- Many times my “MO” involves Judging others, playing God, acting as LJs law enforcement, and never admitting any of my ideas could possibly wrong or anyone else's idea could possibly be correct.-- Hoowaa14 posts in 333 days #4 posted 04-10-2016 04:12 AM I am doing two versions 1. Long side = 34.5 cm 2. Long side = 36 cm Will sketch up give you the length for the short side? Thanks! jbay699 posts in 318 days #5 posted 04-10-2016 04:13 AM If I know the width, it will -- Many times my “MO” involves Judging others, playing God, acting as LJs law enforcement, and never admitting any of my ideas could possibly wrong or anyone else's idea could possibly be correct.-- waho6o97115 posts in 1995 days #6 posted 04-10-2016 04:18 AM Draw a picture Hoowaa14 posts in 333 days #7 posted 04-10-2016 04:36 AM Does this info help? waho6o97115 posts in 1995 days #8 posted 04-10-2016 04:39 AM Thank you jbay699 posts in 318 days #9 posted 04-10-2016 05:09 AM Does this info help? - Hoowaa Nope. They could be anything. Do you have the cross measurement? -- Many times my “MO” involves Judging others, playing God, acting as LJs law enforcement, and never admitting any of my ideas could possibly wrong or anyone else's idea could possibly be correct.-- jerryminer496 posts in 860 days #10 posted 04-10-2016 05:39 AM The pic looks like a regular hexagon (all sides equal), but if two sides are indeed short then maybe this helps?: Tootles779 posts in 1920 days #11 posted 04-10-2016 05:59 AM Regardless of which piece of wood you are dealing within the frame (long or short), the inside edge of each piece of wood is 1.15 times the thickness of the wood shorter than the outside length. So: L inside = L outside – (1.15 * Thickness) This is easier with metric than with imperial units. However, one way to work it out is to cut an angle on one end of a piece of timber that you will be using for the frame. Then measure the distance across the angled end, from the outside edge to the outside edge. That distance is, in fact, 1.15 times the thickness of the timber. -- I may have lost my marbles, but I still have my love of woodworking Tootles779 posts in 1920 days #12 posted 04-10-2016 02:38 PM Sorry, looking back over the whole post, I think I am on the wrong track. I went back and worked this out: Which is just the generic version of what Jerryminer drew up. -- I may have lost my marbles, but I still have my love of woodworking MadMark965 posts in 871 days #13 posted 04-10-2016 02:58 PM Get the tip to tip distance and a board slightly longer with square ends. Rip board to flat-to-flat width. Mark the mid point on one end and set stop. Miter to the center mark at 30°. Flip & cut to make one end. Rotate and repeat. M -- Madmark - Madmark2150@yahoo.com Wiretreefarm.com Hoowaa14 posts in 333 days #14 posted 04-10-2016 09:51 PM I should have paid more attention during geometry class. Who would have thought the info would have been helpful 15 years later. Here is a video that shows size scale charts for hexagons. I was hoping for a calculator or something like what is in this video. https://www.youtube.com/watch?v=lEaCeehLwf8&nohtml5=False jbay699 posts in 318 days #15 posted 04-10-2016 10:47 PM * -- Many times my “MO” involves Judging others, playing God, acting as LJs law enforcement, and never admitting any of my ideas could possibly wrong or anyone else's idea could possibly be correct.--

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