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Blog entry by maryetta posted 09-08-2009 06:27 AM 579 reads 0 times favorited 2 comments Add to Favorites Watch

Can anyone tell me how to calculate the # of CFM of a squirrel cage motor that is needed to adequately move air based on the cubic feet of a wood shop?

-- Maryetta, Alabama, maryettapalmer@yahoo.com



2 comments so far

View Jimi_C's profile

Jimi_C

507 posts in 2703 days


#1 posted 09-08-2009 07:00 AM

That’s pretty easy, if you know the cubic feet of your shop (sq. feet * ceiling height) just figure out how often you want the air recycled. If your shop is 1000 cu.ft. and you want the air cycled twice/minute, you’d need a 2000CFM motor.

That’s a bit of a generalization, but close enough for wood shop purposes.

-- The difference between being defeated and admitting defeat is what makes all the difference in the world - Upton Sinclair, "The Jungle"

View MedicKen's profile

MedicKen

1610 posts in 2930 days


#2 posted 09-08-2009 07:03 AM

Cubic foot volume of shop Number of air changes per hour Cubic feet per min(cfm) air
(length x width x height) in feet X (6 hobby use, 8 full use) movement capacity of air
————————————————————————————————————————————————————— = filtration device 60
( division necessary to convert cubic feet per hour to cubic feet per min(cfm)

Taken from Woodshop dust Control by Sandor Nagyszalanczy

-- My job is to give my kids things to discuss with their therapist....medic20447@gmail.com

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